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Scriti E(x) sub forma de fractie algebrica ireductibila:

E(x)=(1 supra x²-10x+25) - (1 supra x²-2x+1)

Răspuns :

Acidor
nustiu daca am inteles corect conditia, sper sa te ajute
Vezi imaginea Acidor
Mariangel
E(x) = [tex] \frac{1}{ x^{2} -10x+25} - \frac{1}{ x^{2} -2x+1} [/tex] =

= [tex] \frac{1}{ (x-5)^{2} } [/tex] - [tex] \frac{1}{ (x-1)^{2} } [/tex] =

= [tex] \frac{ (x-1)^{2} }{ (x-5)^{2} * (x-1)^{2} } [/tex] - [tex] \frac{ (x-5)^{2} }{ (x-1)^{2} * (x-5)^{2} } [/tex] =

= [tex] \frac{ (x-1)^{2} - (x-5)^{2} }{ (x-5)^{2} * (x-1)^{2} } [/tex]=

= [tex] \frac{ x^{2} -2x+1- x^{2} +10x-25}{ (x-5)^{2} * (x-1)^{2} } [/tex]=

= [tex] \frac{8x-24}{ (x-5)^{2} * (x-1)^{2} } [/tex]=


= [tex] \frac{8(x-3)}{ (x-5)^{2} * (x-1)^{2} } [/tex]










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