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a fost răspuns

Descompuneti in factori
a) 3x²-6x+9
b) x²+4x+4
c)9x²-6x+1
d)(x²-3)²-x²·²
e) (2x-3)²-(x+6)²

Răspuns :

Lucasela

a) x²-6x+9=(x-3)²

b) x²+4x+4=(x+2)²

c)9x²-6x+1=(3x-1)²

d)(x²-3)²-x²·²=(x²-3-x²)(x²-3+x²)=-3(2x²-3)=3(3-2x²)

e) (2x-3)²-(x+6)² =(2x-3-x-6)(2x-3+x+6)=(x-9)(3x+3)=3(x-9)(x+1)

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