Răspuns :
1. x² -3x >=0 <=> x(x-3) >=0 <=> x >=0 si x-3 >=0 => x >=3 dar x∈R => x∈[3,∞) sau x <=0 si x-3 <=0 => x <=3 dar x∈R => x∈(-∞,0] .
Asadar x∈(-∞,0] ∪ [3,∞) .
2. 2-4x >=0 <=> 4x <=2 <> x <=1/2 dar x∈R => x∈(-∞,1/2] .
3. -x² +3x -2 >=0 => -x² +3x -2=0 => Δ=b²-4ac=9-4·(-1)·(-2)=9-8=1 .
x=-b+-√Δ /2a => x=-3-1 /-2 =2 sau x=-3+1 /-2 =1 => x∈[1,2] .
4. 2x² -3x +1 >=0 <=> 2x² -3x +1 =0 => Δ=b² -4ac=9-4·2·1=1 .
x=-b+-√Δ /2a => x=3-1 /4 =1/2 sau x=3+1 /4 =4/4=1 =>x∈[1/2,1] .
3+x >=0 => x >-3 <=> x∈[1/2,1] .
5. x² -x +1 >=0 => x∈(-∞,∞) .