modulul se anileaz pt 2x+3=0 deci x=-3/2
Discutie:
a) pt x>-3/2
3(2x+3+4x-9)+5=4x+36+8x-16
3(6x-6)+5=12x+20
18x-18+5=12x+20
6x-13=20
6x=33 | împartim prin 3
2x=11
x=11/2>0>-3/2 deci solutia convine
pt x<-3/2
3(-2x-3+4x-9)+5=12x+20
3(2x-12)=12x+20
4x-36=12x+20 impartim toat relatia prin 4
x-9=3x+5
-9-5=3x-x
-14=2x
2x=-14
x=-7<-3/2 solutia convine
c) pt x=-3/2
4x-9+5=12x-20
4x-4=12x-20
x-1=3x-5
4=2x
x=2 , contradictie, -3/2 nu e solutie
x∈{-7;11/2}
