Răspuns :
a+b+c=30
a,b,c= nr. consecutive =>
b=a+1
c=a+2
=> a+a+1+a+2=30
3a+3=30
3a=30 - 3
3a=27
a= 27 : 3
a=9
b=a+1
b=9+1
b=10
c=a+2
c=9+2
c=11
a,b,c= nr. consecutive =>
b=a+1
c=a+2
=> a+a+1+a+2=30
3a+3=30
3a=30 - 3
3a=27
a= 27 : 3
a=9
b=a+1
b=9+1
b=10
c=a+2
c=9+2
c=11