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Deaculivia34
a fost răspuns

A )Nr de moli de substanță care se gasesc in 
A)213g Cl2
B)219h Hcl
3)144g H20
Va rog !

Răspuns :

Pokju8888

213 g  Cl2

1mol Cl2---------2.35,5 g

x moli-----------213g

x= 213:71 = 3 moli Cl2


219 g HCl

MHCl= 1+ 35,5= 36,5------->1mol=36,5g

1mol HCl ----------36,5 g HCl

x moli--------------219g

x=219: 36,5=6 moli HCl


144g H2O

MH2O=2+16=18------->1mol=18g

1mol H2O------------------18g

xmoli-----------------------144g

x=144: 18 = 8 moli H2O

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