A. aplica relatia n(niu)=m/M(miu)
n(niu)Cl2= 213g/71g/mol=
nHCl=219g/36,5g/mol=
nH2O=144g/18g/mol=
B. aplicaegalitatea n(niu)= V/Vm=m/M(miu)---> V=mxVm/M, unde Vm= 22,4l/mol este volumul molar
VCl2= 149gx22,4l/mol/ 71g/mol=
V,HCl= 146 g??x22,4l/mol/ 36,5g/mol=
finalizeaza calculele !!!!!