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Hillergaming6
a fost răspuns

Aflati:
Dau coroana!

A={xIx ∈ N,2
B={xIx ∈ N,x=2*k,k∈N,k<6}

C= {xIx ∈ N,x =2+k,k∈ N,k<6}

D= {xIx ∈N ,x =2^k,k∈N,k≤3}

Răspuns :

Albatran

A=??nu ai specificat

B={0;2;4;6;8;10}  am inmultit cu 2 numerele naturale4de la 0 la 5

C={2;3;4;5;6;7} am adunat 2 la numerele naturalede la 0 la 5

D={1;2;4;8} am ridicat pe 2 succesiv la puterile 0,1 si,respectiv, 2

aS SIMPLE AS THAT!!!

Icecon2005

A={xIx ∈ N,2  ???????????

B={xIx ∈ N,x=2×k,k∈N,k<6}

k ∈ {0, 1, 2, 3, 4, 5}

x = 2 × k = 2 × 0 =0;  

x = 2 × k = 2 ×  1 = 2  

x = 2 × k = 2 × 3 = 6  

x = 2 × k = 2 ×  4 =8  

x = 2 × k = 2× 5  =10;  

B = { 0 , 2 ,4 ,6 , 8, 10}

C= {xIx ∈ N,x =2+k,k∈ N,k<6}

k ∈ {0, 1, 2, 3, 4, 5}

x = 2 + k = 2 + 0 = 2  

x = 2 + k = 2 + 1 = 3  

x = 2 + k = 2 +  2 = 4  

x = 2 + k = 2 +  3 = 5  

x = 2 + k = 2 + 4 = 6  

x = 2 + k = 2 + 5  = 7  

C = { 2, 3, 4, 5, 6, 7 }

D= {xIx ∈N ,x =2^k,k∈N,k≤3}

k ∈ { 0, 1, 2, 3}

D ∈ { 2⁰, 2¹, 2², 2³}⇒D ∈ { 1, 2 , 4 ,8}

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