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Florentinaconst
a fost răspuns

Calculati media aritmetica ponderata a numerelor 2 3/4,3 4/5,4 5/6, cu ponderile 4, 5 si respectiv 6.

Răspuns :

[tex]\frac{4* \frac{23}{4}+5* \frac{34}{5} +6* \frac{45}{6} }{4+5+6} (simlplificam~ce~putem~adica~4~cu~4 , 5~cu ~5~si~ 6~cu~6\\\\= \frac{ 23+34+45 }{15} \\\\ = \frac{102}{15} \\\\ \boxed{=6,8}. [/tex]

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