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Bidy
a fost răspuns

i) 14+6-{8+[7-(3+2)]}=
j) [14-(16-2)]-[8-(7+3-2)]=
k)100-{27-(5+1)-[13-(10-3)]}=
l) 18-(16-2)-{[3+(4-1)]-[5-(3-2)]}=
Va roggg ajutati-ma!!!!

Răspuns :

l)14+6-{8+[7-(3+2)]}=20 -{8+[7-5]}= 20-{8+2}=20-10=10
j)[14-(16-2)]-[8-(7+3-2)]
=[14-14]-[8-8]
=0-0
=0

k)100-{27-(5+1)-[13-(10-3)]}=
=100-{27-6-[13-7]}
=100-{21-6}
=100-1
=85

l)18-(16-2)-{[3+(4-1)]-[5-(3-2)]}=
=18-14-{[3+3]-[5-1]}
=4-{6-4}
=4-2
=2

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