Răspuns :
x²+5x+6 = 0 a = 1, b = 5, c = 6 Delta = b² - 4ac = 25 - 4*1*6 = 25 - 24 = 1 x1,2 = (-b +/- √delta)/2a x1 = (-5+1)/2 = -4/2 = -2 x2 = (-5-1)/2 = -6/2 = -3
x²+5x+6=0
x²+3x+2=0
x•(x+3)+2x+6=0
x•(x+3)+2(x+3)=0
(x+3)•(x+2)=0
x+3=0=>x=-3
x+2=0=>x=-2
[tex] = > x_{1} = - 3 \\ \\ \: \: \: \: \: \: \: \: x_{2} = - 2 [/tex]
x²+3x+2=0
x•(x+3)+2x+6=0
x•(x+3)+2(x+3)=0
(x+3)•(x+2)=0
x+3=0=>x=-3
x+2=0=>x=-2
[tex] = > x_{1} = - 3 \\ \\ \: \: \: \: \: \: \: \: x_{2} = - 2 [/tex]