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Determinati numarul natural X Din : 2+4×[3-(X+2)]=6 Va rog ajutati.ma . Dau coroana

Răspuns :

4x[3-(x+2)]=6-2
4x[3-(x+2)]=4
[3-(x+2)=4:4
[3-(x+2)=1
(x+2)=3-1
x+2=2
x=2-2
x=0
102533

2+4·[3-(X+2)]=6 <=> 4·[3-(X+2)]=6-2 <=> [3-(X+2)]=4:4

<=> -(X+2) = 1-3 <=> -x-2 = -2 => x = -2+2 => x = 0