a+b+c = 297
a:b = 2 r 25 <=> a= 2b+25 => b = (a-25)/2
a:c = 11 r 8 <=> a = 11c +8 => c = (a-8)/11
²²⁾a+¹¹⁾(a-25)/2 + ²⁾(a-8)/11 = ²²⁾297 =?
22a + 11a - 275 + 2a -16 = 6534
35a = 6534+275+16 => 35a = 6825 => a = 6825:35
a = 195
b = (195-25)/2 = 170/2 => b = 85
c = (195-8)/11 = 187/11 => c = 17
a+b+c = 195+85+17 = 297, corect.