[tex]\it \left(\dfrac{^{4)}1}{\ 2}-\dfrac{1}{8}\right)\cdot2^4 = \dfrac{4-1}{8}\cdot16=\dfrac{3}{8}\cdot\dfrac{16}{1} = \dfrac{48}{8} = 6[/tex]
1 supra 2 il amplificam cu 4 =4/8- 1/8 =3/8 x 16= 48/8
sper ca te-am ajutat
