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a fost răspuns

A) 1 supra 201 +2 supra 201 +.... +201 supra 201
B= 5,2+ 5,(2)-5,02-5,0(2)

Răspuns :

Silics
A= (1+2+...+201)/201
A= (201×202/2)/201
A= (201×101)/201
A=101

B=
[tex] \frac{52}{10} + 5 \frac{2}{9} - \frac{502}{100} - 5 \frac{2}{90} [/tex]
B= 52/10 + 47/9 - 502/100 - 452/90
B= 520/100 + 470/90 -502/100 -452/90
B= 18/100 + 18/90
B= 162/900 + 180/900
B= 342/900
B= 0.18

sper ca e bine si ca te-am ajutat

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