Răspuns :
a+b+c+d=58
a+1=b a+2=c a+3=d (58-6):4=52:4=13(a)
b=14 c=15 d=16
notez cu a,a+1,a+2,a+3 nunerele naturale consecutive.
a+a+1+a+2+a+3=58
4a+6=58
4a=58-6
4a=52
a=52÷4
a=13
Numerele sunt: 13,14,15,16
a+a+1+a+2+a+3=58
4a+6=58
4a=58-6
4a=52
a=52÷4
a=13
Numerele sunt: 13,14,15,16