A=-4
B=5+Radical din 2
A<B
[tex]\frac{1}{2+\sqrt{5} } + \frac{1}{2-\sqrt{5} } = \frac{2-\sqrt{5} }{4-5}+ \frac{2+\sqrt{5} }{4-5} =\frac{2-\sqrt{5} }{-1} +\frac{2+\sqrt{5} }{-1} =-(2-\sqrt{5})+-(2+\sqrt{5})= -2+\sqrt{5}-2-\sqrt{5}=-2-2=-4 (1+\sqrt{2}) ^{2} +2=1+2\sqrt{2} +2+2=5+\sqrt{2}[/tex]
