Răspuns :
3x² +4x -4 =0 => x₁ = [-4+√(16+48)]/6 = [-4+8]/6 = 4/6 = 2/3
x₂ = (-4-8)/6 = -2
3x²+4x-4=0
a=3;b=4;c=-4
Δ=b²-4ac=4²-4*3*(-4)=16+48=64
x₁=(-b+√Δ)/2a=(-4+√64)/2*3=(-4+8)/6=4/6=2/3
x₂=(-b-√Δ)/2a=(-4-√64)/2*3=(-4-8)/6=-12/6=-2
x∈{-2;2/3}
3x² +4x -4 =0 => x₁ = [-4+√(16+48)]/6 = [-4+8]/6 = 4/6 = 2/3
x₂ = (-4-8)/6 = -2
3x²+4x-4=0
a=3;b=4;c=-4
Δ=b²-4ac=4²-4*3*(-4)=16+48=64
x₁=(-b+√Δ)/2a=(-4+√64)/2*3=(-4+8)/6=4/6=2/3
x₂=(-b-√Δ)/2a=(-4-√64)/2*3=(-4-8)/6=-12/6=-2
x∈{-2;2/3}