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Aleyna1278
a fost răspuns

fie f:r->r,f(x)=(m^2-1)x+m+1. aratati ca f(1)>sau egal -1/4

Răspuns :

PeakyBlinder

[tex] f(x)=(m^2-1)x+m+1 \\ \\f(1)=m^2-1+m+1=m^2+m\geq-\frac{1}{4} \\\\m^2+m+\frac{1}{4}\geq 0\\ \\(m+\frac{1}{2})^2\geq0~(Adevarat) [/tex]

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