→ intoduc intregii in fractie
5 intregi si 1 / 8 = ( 5 x 8 + 1 ) / 8 = 41 / 8
[ 3 ( x + 1 / 5 ) · 7 / 2 - 4 ] · 3 + 4 = 41 / 8
[ 3 ( x + 1 / 5 ) · 7 / 2 - 4 ] · 3 = 41 / 8 - 4 = ( 41 - 32 ) / 8 = 9 / 8
3 ( x + 1 / 5 ) · 7 / 2 - 4 = 9 / 8 : 3 = 9 / 8 × 1 / 3 = 3 / 8
3 ( x + 1 / 5 ) · 7 / 2 = 3 / 8 + 4 = ( 3 + 32 ) / 8 = 35 / 8
3 ( x + 1 / 5 ) = 35 / 8 : 7 / 2 = 35 / 8 · 2 / 7 = 5 / 4
x + 1 / 5 = 5 / 4 : 3 = 5 / 4 · 1 / 3 = 5 / 12
x = 5 / 12 - 1 / 5
x = ( 25 - 12 ) / 60 = 13 / 60 → am folosit metoda mersului invers
x = 13 / 60
