Răspuns :
[tex] \it x^3-4x^2-x+4= x^2(x-4) -(x-4) = (x-4)(x^2-1) = (x-4)(x-1)(x+1)
\\ \\
x^2-5x+4=x^2-4x-x+4=x(x-4-()x-4) =(x-4)(x-1)
\\ \\ \\
F = \dfrac{(x-4)(x-1)(x+1)}{(x-4)(x-1)} = x+1 [/tex]
[tex] \it x^3-4x^2-x+4= x^2(x-4) -(x-4) = (x-4)(x^2-1) = (x-4)(x-1)(x+1)
\\ \\
x^2-5x+4=x^2-4x-x+4=x(x-4-()x-4) =(x-4)(x-1)
\\ \\ \\
F = \dfrac{(x-4)(x-1)(x+1)}{(x-4)(x-1)} = x+1 [/tex]