f'(x)=3x²+1/x>0, ∀x∈(0;∞)
deci f(x) crescatoare pe domenul de definitie
f(1)=1³+ln1=1+0=1
∀x≥1, f(1)≥f(1)=1 ptca functia estecrescatoare\
as simple as that!!!
