Răspuns :
[tex] \it \sqrt[3]{\it64} +\sqrt{18} -3\sqrt2=\sqrt[3]{\it4^3} +\sqrt{9\cdot2} -3\sqrt2 =4+3\sqrt2-3\sqrt2= 4 \in\mathbb{N} [/tex]
[tex] \it \sqrt[3]{\it64} +\sqrt{18} -3\sqrt2=\sqrt[3]{\it4^3} +\sqrt{9\cdot2} -3\sqrt2 =4+3\sqrt2-3\sqrt2= 4 \in\mathbb{N} [/tex]