[tex] \frac{\frac{3x}{4}-1}{3}+\frac{x}{4}=\frac{4x-3}{6}\\\frac{\frac{3x-4}{4}}{3}+\frac{x}{4}=\frac{4x-3}{6}\\\frac{3x-4}{12}+\frac{x}{4}-\frac{4x-3}{6}=0\\\frac{3x-4+3x-2(4x-3)}{12}=0\\\frac{3x-4+3x-8x+6}{12}=0\\\frac{2-2x}{12}=0\\\frac{2(1-x)}{12}=0\\\frac{1-x}{6}=0\\1-x=0\\-x=-1\\x=1 [/tex]
S={1}
