Răspuns :
ABC Δ dreptunghic
m(∡A)=90°; AB/AC = 3/4
AB/AC=3/4 ⇒ AB/3=AC/4=k ⇒
AB = 3k si AC = 4k
ΔABC Teorema lui Pitagora⇒
BC²=AB²+AC²=(3k)²+(4k)²=9k²+16k²=25k²
⇒BC=5k
Intr-un triunghi dreptunghic inaltimea este (C₁×C₂)/Ipotenuza
AD = (AB×AC)/BC=(3k×4k)/5k=12k²/5k=12k/5=24 ⇒k=(24×5)/12=10
⇒AB=3k=3×10=30 AC=4k=4×10=40 BC=5k=5×10=50
P = AB+AC+BC=30+40+50 = 120 cm
A = AB×AC/2= 30×40/2 = 600 cm²
Am anexat o rezolvare in plus ----
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