1 2 3
a x y
x si y pot lua independent cate 4 valori (a,b,c,d)...total 4*4=16 functii, CORECT (ca in bancul cu SUV-ul 4*4...)
(1+√2)^100
Tk+1=Cnluatecate k 1^(100-k)* (√2)^k
unde k∈{0;1...100}
cate numere pare exista in multimea {0;1;2;3...99;100}?? pt ca (√2)^k=2^(k/2)
exista 0;2;4...100= 2*0;2*1;2*2...2*50 in total 51 de numere
deci 51 de termeni rationali (si 50 irationali, dacă te intreaba cineva suparat/ă ca ai stiut primul raspuns)