Răspuns :
cele patru nr sunt
a,a+1,a+2,a+3
a+a+3=613
2a=610
a=305
termenii sunt
305,306,307,308
a,a+1,a+2,a+3
a+a+3=613
2a=610
a=305
termenii sunt
305,306,307,308
a|__×_|
b|__×_|+1
c|__×_|+2
d|__×_|+3
a+d=613 daca inlocuim obtinem:
x+x+3=613
2x+3=613
2x=613-3
2x=610⇒x=610:2
x=305 ⇒a=305
b=306
c=307
d=308
b|__×_|+1
c|__×_|+2
d|__×_|+3
a+d=613 daca inlocuim obtinem:
x+x+3=613
2x+3=613
2x=613-3
2x=610⇒x=610:2
x=305 ⇒a=305
b=306
c=307
d=308