2sin30⁰cos30⁰-cos30⁰tg45⁰ = ?
sin30⁰ = 1/2 ; cos30⁰ = (√3)/2 ; tg45⁰ = 1
=> 2sin30⁰cos30⁰-cos30⁰tg45⁰ = 2 x 1/2 x (√3)/2 - [(√3)/2] x1 = 0
2sin30⁰cos30⁰-cos45⁰tg30⁰ = ?
cos45⁰ = (√2)/2 ; tg 30⁰ = (√3)/3
2sin30⁰cos30⁰-cos45⁰tg30⁰ =2 x 1/2 x (√3)/2 - [(√2)/2] x (√3)/3 =
(√3)/2 - (√6)/6 = (3√3 - √6)/6 = [3√3(1-√2)]/6 = [(√3)/2](1-√2)
