Răspuns :
a)<AOD=360-(46-78-135)=101*
b)23*+36*=59*(imparti masura fiecarui unghi la 2)
m(∡AOD)=360°-135°-78°-46°=101°
masura dintre bisectoare=46°/2+78°/2=23°+39°=62°
m(∡B'OC)=180°-78°=102°
a)<AOD=360-(46-78-135)=101*
b)23*+36*=59*(imparti masura fiecarui unghi la 2)
m(∡AOD)=360°-135°-78°-46°=101°
masura dintre bisectoare=46°/2+78°/2=23°+39°=62°
m(∡B'OC)=180°-78°=102°