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PsSiNNNeR
a fost răspuns

Vreau si eu 10 ecuati si 10 inecuati de nivelul clasei a 6 .Rezolvate@@@.Cine pote sa ma ajute.Si sa fie rezolvate corect.Ms mult.@@@


Răspuns :

Ecuații:

x+7=9=>x=9-7=2

x-3=7=>x=7+3=10

x-8=5=>x=5+8=13

x+2=7=>x=7-2=5

14+3x=31=>x=31-14=17

21-x=12=>-x=12-21=-9=>x=9

43+x=-1=>x=-43+1=-44

39-x=-6=>x=-39-6=-45

2x+1=4=>2x=-1+4=3

[tex] \frac{2x}{2} = \frac{3}{2} = > x = \frac{3}{2} [/tex]

4x+2=7=>4x=-2+7=5

[tex] \frac{4x}{4} = \frac{5}{4} = > x = \frac{5}{4} [/tex]

Inecuații:

x-5<7

x<7+5

x<12

-x-7>-2

-x>-2+7

-x>5

x<-5

4-x>12

-x<12-4

-x<8

x>-8

x-2≤3

x≤3+2

x≤5

-x+13≥5

13-x≥5

-x≥5-13

-x≥-8

x≤8

4x+2>6

4x>6-2

4x>4

x>1

2x-5<3

2x<3+5

2x<8

x<[tex] \frac{8}{2} [/tex]

x<4

6+x>9

x>9-6

x>3

-4x-15>5

-4x>5+15

-4x>20

[tex]x \: < - \frac{20}{4} [/tex]

x<-5

8-7x<15

-7x<15-8

-7x<7

x>-1