Răspuns :
[tex] \it sinC=\dfrac{cateta\ opus\breve{a}}{ipotenuz\breve{a}} = \dfrac{AB}{BC} =\dfrac{ \ 14^{(2}}{20} =\dfrac{7}{10} = 0,7 [/tex]
[tex] \it sinC=\dfrac{cateta\ opus\breve{a}}{ipotenuz\breve{a}} = \dfrac{AB}{BC} =\dfrac{ \ 14^{(2}}{20} =\dfrac{7}{10} = 0,7 [/tex]