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Lorandraczowzuu3
a fost răspuns

Rezolvati ecuatiile:
a)2{3(2x-1)-2[3(x=40-2(x+6)]}=3[8-5(3x-2)]-7
b)3{2(3x+2)-3[2(3x+5)-3(x+4)]}=5[4-3(2x-9)]-41

Răspuns :

Maverickarcher

a) e pus un egal aiurea
b) 3(6x+4-3(6x+10-3x-12))=5(4-6x+27)-41
3(6x+4-9x+6)=114-30x
3(-3x+10)=114-30x
-9x+30=114-30x
21x=84 => x=4

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