Desenul stii sa faci tu. Trecem la b)
Din "piramida triungiulara regulata VABC" => ABC-triunghi echilateral
[tex] A_{bazei} =\frac{6^{2}\sqrt{3}}{4} =9\sqrt{3} \\
V=\frac{A_{bazei}*h}{3} =3\sqrt{3} \\ [/tex]
Trecem la c)
[tex] A_{laterala}= \frac{P_{bazei*Apotema}}{2} =\frac{18*Ap}{2} =9*Ap\\
[/tex]
[tex]\left \{ {{Ducem.VM.perpediculara.pe.BC} \atop {Ducem.VO.perpediculara.pe.tr. ABC}} \right.=\ \textgreater \ AM=\frac{6\sqrt{3}}{2} =3\sqrt{3} \\
[/tex]
[tex]OM=\frac{1}{3}*3\sqrt{3}=\sqrt{3} \\
VM=Ap=\sqrt{1^{2}+3} =\sqrt{4} =2cm \\ =\ \textgreater \ A_{laterala} =9*2= \\ =18cm^{2} [/tex]
