Răspuns :
[tex] 2^{x} + 16 * \frac{1}{2^{x}} = 10 | * 2^{x}
\\ 2^{2x} + 16 = 10 * 2^{x}
\\ Notam: 2^{x} = t
\\ t^{2} + 16 = 10t
\\ t^{2} - 10t + 16 = 0
\\ D = 100 - 64 = 36
\\ t_{1} = 8 => 2^{x} = t => 2^{x} = 8 => x = 3
\\ t_{2} = 2 => 2^{x} =t => 2^{x} = 2 => x = 1 [/tex]