6xy - 3x + 2y =10
x(6y - 3 + 2y) = 10
x = [tex] \frac{10}{8y - 3} [/tex]
inlocuim pe x
6y * [tex] \frac{10}{8y - 3} [/tex] - 3 * [tex] \frac{10}{8y - 3} [/tex] + 2y = 10
[tex] \frac{60y}{8y - 3} - \frac{30}{8y - 3} + \frac{2y(8y-3)}{8y - 3} = \frac{10(8y-3)}{(8y-3)} [/tex]
60y - 30 + [tex] 16y^{2} [/tex]- 6y = 10(8y-3)
60y - 30 + [tex] 16y^{2} [/tex]- 6y =80y - 30
60y - 30 + [tex] 16y^{2} [/tex] - 6y - 80y + 30 = 0
16y^2 - 26y = 0
y ( 16 y - 26 ) = 0
16 y - 26 = 0
y = [tex] \frac{26}{16} [/tex] = [tex] \frac{13}{8} [/tex]
x = [tex] \frac{10}{ \frac{8x13}{8-3}} [/tex]
x = [tex] \frac{10}{ \frac{104}{8} - 3} [/tex]
x = [tex] \frac{10}{ \frac{104 - 24}{8}} [/tex]
x = [tex] \frac{10}{10} [/tex]
x = 1
Verificam
6x1x[tex] \frac{13}{8} [/tex] - 3x1 + 2x[tex] \frac{13}{8} [/tex] = 10
[tex] \frac{78}{8} - \frac{24}{8} + \frac{26}{8} [/tex] = 10
[tex]\frac{80}{8}[/tex] = 10
10 = 10 ADEVARAT
Vacanta placuta in continuare!
Succes!
