[tex]\displaystyle \limit \lim_{x\to \infty}(e^{x^2}-x^2-1})=\lim_{x\to \infty}\left(x^2\left(\dfrac{e^x^2}{x^2}-1-\dfrac{1}{x^2}}\right)\right)=\infty(\infty -1)=\boxed{\infty}\\
\text{Obs:}\lim_{x\to \infty} \dfrac{e^x^2}{x^2}=\infty \text{ se poate demonstra foarte usor cu l'Hospital.}[/tex]
