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Chris13
a fost răspuns

Rezolvati in R: |x-1|+|2-2x|=12

Răspuns :

[tex]\text{Folosim faptul ca }|a|=|-a|\\ |x-1|+|2-2x|=12\\ |x-1|+2|1-x|=12\\ |x-1|+2|x-1|=12\\ 3|x-1|=12\\ |x-1|=4\\ i)x-1=4\Rightarrow x_1=5\\ ii)x-1=-4\Rightarrow x_2=-3\\ S:x\in \{-3,5\}[/tex]
Triunghiu
|x-1|+|2-2x|=12
lx-1l+2l1-xl=12
lx-1l+2lx-1l=12
3lx-1l=12    l :3
lx-1l=4
a) x-1=4
x=4+1
x=5
b) x-1=-4
x=-4+1
x=-3
x∈{-3, 5}

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