Răspuns :
teorema catetei : AB/BC=BD/AB, [tex] AB^{2} [/tex]=BCxBD, aflam BC=BD+CD =3+9=12cm, [tex] AB^{2} [/tex]=12x3=36, AB=[tex] \sqrt{36} [/tex]=6cm
teorema inaltimii in tr.dr ABC
AD=√BD*DC=3√3
Pitagora in tr dr ADB
AB=√(BD²+AD²)=√(3²+(3√3)²)=6cm
vezi desen
AD=√BD*DC=3√3
Pitagora in tr dr ADB
AB=√(BD²+AD²)=√(3²+(3√3)²)=6cm
vezi desen