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a fost răspuns

cum derivez ln | x+1 | ???

Răspuns :

[tex]\text{Mai intai hai sa explicitam modulul.} \\ f(x)= \left \{ {{\ln(x+1),x\geq -1} \atop ln(-1-x),x\ \textless \ -1}} \right.\\ \text{Prin urmare:}\\ f'(x)= \left \{ {{\dfrac{1}{x+1},x\geq -1} \atop {\dfrac{-1}{-x-1},x\ \textless \ -1}} \right. = \dfrac{1}{x+1}\ \forall x\ \in \mathbb{R}[/tex]

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