Răspuns :
x² - 7x + 12 = 0
Δ = b² - 4ac = 49 - 4×12×1 = 49 - 48 = 1
x₁ = (-b +√Δ) / 2a = (7 +1)/2 = 8/2 = 4
x₂ = (-b -√Δ) / 2a = (7 - 1)/2 = 6/2 = 3
x = {3; 4}
Δ = b² - 4ac = 49 - 4×12×1 = 49 - 48 = 1
x₁ = (-b +√Δ) / 2a = (7 +1)/2 = 8/2 = 4
x₂ = (-b -√Δ) / 2a = (7 - 1)/2 = 6/2 = 3
x = {3; 4}
x²-7x+12=0⇔x²-3x-4x+12⇔x(x-3)-4(x-3)=0⇔(x-4)(x-3)=0⇔
⇔x₁-4=0⇔x₁=4;
x₂-3=0⇔x₂=3;
R:S={3;4}
Bafta!
⇔x₁-4=0⇔x₁=4;
x₂-3=0⇔x₂=3;
R:S={3;4}
Bafta!