Răspuns :
z=1+i
z^2-2i=0
(1+i)^2-2i=0 => 1+2i+i^2-2i=0 =>
1+i^2=0 => i^2= -1 => i=1
z=1+1 => z=2
V: 2^2- 2x2= 4-4=0
z^2-2i=0
(1+i)^2-2i=0 => 1+2i+i^2-2i=0 =>
1+i^2=0 => i^2= -1 => i=1
z=1+1 => z=2
V: 2^2- 2x2= 4-4=0