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a fost răspuns

Ma ajutati si pe mine,va rog???????

Ma Ajutati Si Pe Mineva Rog class=

Răspuns :

f'(x)=3x^2-2x-1
x1,2=(2+-radical16)/6=(2+-4)/6
x1=-1/3  x2=1

f"(x) =6x-2=2(3x-1)

x |- ∞                         -1/3                 1/3       1                           ∞
f(x)    creste               maxim scade          minim     creste
f'(x)   ++++++++++++0  ---------------------    0+++++++++++++++

f'(x) -------------------------------------------0++++++++++++++++++++
        CONCAVA                               pct.inflex      CONVEXA

f(-1/3) =...vezi tu, minim LOCAL
f(1)=1 , maxim LOCAL