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Ionascurobert1pa9fcd
a fost răspuns

sa se simplifice raportul x²-2x- 3 supra x²-6x+9

Răspuns :

Turcanuliuba19
x^2-2x-3=(x-3)(x+1)
x^2-6x+9=(x-3)^2          =>
 
(x-3)(x+1) / (x-3)^2=(x+1) / (x-3)

PS: ^ -putere
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Icecon2005
[tex] \frac{ x^{2} -2x-3}{ x^{2} -6x+9}= \frac{(x-3)(x+1)}{(x-3)(x-3)} = \frac{x+1}{x-3} \\ \\ [/tex]


x²-2x-3=x²-3x+x-3=x(x+1)-3(x+1)=(x-3)(x+1)

x²-6x+9=x²-3x-3x+9=x(x-3)-3(x-3)=(x-3)(x-3)

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