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Animus05
a fost răspuns

Să se calculeze cantitatea de oxigen continută în 224g hidroxid de potasiu.
Se dau Ah=1 , Ak=39 ,Ao= 16.


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Răspuns :

Pokju8888
KOHM=39+16+1=56--------->1mol=56g                                                                                    56g KOH---------16g O                                                                                                                                             224 gKOH----------Xg O                                                                                                  X=224.16:56=64 gO