Răspuns :
a:b=3 r 2⇒a=3b+2
b:c=3 r 2⇒b=3c+2
a=3·(3c+2)+2
a=9c+6+2=9c+8
a-b=328
3b+2-b=328
2b=326
b=326:2
b=163
a=328+163
a=491
491=9c+8
9c=483
c=483:9
c=53,(6)
b:c=3 r 2⇒b=3c+2
a=3·(3c+2)+2
a=9c+6+2=9c+8
a-b=328
3b+2-b=328
2b=326
b=326:2
b=163
a=328+163
a=491
491=9c+8
9c=483
c=483:9
c=53,(6)
a : b = 3 rest 2 ⇒ a = 3 × b + 2
b : c = 3 rest 2 ⇒ b = 3 × c + 2
a - b = 328
3 × b + 2 - b = 328
2 × b = 326
b = 326 : 2
b = 163 → al doilea numar
a = 3 × 163 + 2 = 489 + 2 = 491 → primul nr.
3 × c + 2 = 163
3 x c = 161
c = 161 : 3
c = 53,(6) → al treilea nr.
b : c = 3 rest 2 ⇒ b = 3 × c + 2
a - b = 328
3 × b + 2 - b = 328
2 × b = 326
b = 326 : 2
b = 163 → al doilea numar
a = 3 × 163 + 2 = 489 + 2 = 491 → primul nr.
3 × c + 2 = 163
3 x c = 161
c = 161 : 3
c = 53,(6) → al treilea nr.