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Aratati ca radical 3(2-radical 2)+radical2(radical3-radical6)=0

Răspuns :

   
[tex]\displaystyle\\ \sqrt3(2-\sqrt2)+\sqrt2(\sqrt3-\sqrt6)=\\\\ =2\sqrt3-\sqrt6+\sqrt6-\sqrt2\sqrt6=\\\\ =2\sqrt3-\sqrt6+\sqrt6-\sqrt2 \cdot\sqrt2\sqrt3=\\\\ =\underline{2\sqrt3}-\underline{\underline{\sqrt6}}+\underline{\underline{\sqrt6}}-\underline{2\sqrt3}=0 [/tex]



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