Răspuns :
Apatrat=lxl=[tex] l^{2} [/tex], l =3cm, A=3x3=9[tex] cm^{2} [/tex], l=12m, A=12x12=144[tex] m^{2} [/tex], 2,5dam, A=2,5x2,5=6,25[tex] dam^{2} [/tex] l=0,3km, A=0,3x0,3=0,09[tex] km^{2} [/tex], l=120mm, A=120x120=14400[tex] mm^{2} [/tex], l=0,01hm, A=0,01x0,01=0,0001[tex] hm^{2} [/tex], l=7,5cm, A=7,5x7,5=56,25[tex] cm^{2} [/tex], l=4,5dm,
A=4,5x4,5=20,25[tex] dm^{2} [/tex]
A=4,5x4,5=20,25[tex] dm^{2} [/tex]
Aria pătratului este l² (latura la patrat)
a) A= 3² =9 cm²
b) A= 12² =144 m²
c) A= (2,5)²= 6,25 dam²
d) A= (0,3)²= 0,09 km²
e) A= 120² = 14400 mm²
f) A= (0,01)² = 0,0001 hm²
g) A= (7,5)² = 56,25 cm²
h) A= (4,5)² = 20,25 dm²
a) A= 3² =9 cm²
b) A= 12² =144 m²
c) A= (2,5)²= 6,25 dam²
d) A= (0,3)²= 0,09 km²
e) A= 120² = 14400 mm²
f) A= (0,01)² = 0,0001 hm²
g) A= (7,5)² = 56,25 cm²
h) A= (4,5)² = 20,25 dm²