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calculeaza: {8+2x[9+9x(7+2x3)]}x2-4x23

Răspuns :

Beatrizparvu
[8+2×(9+9×13)]×2-4×23=
=[8+2×(9+117)]×2-4×23=
=(8+2×126)×2-4×23=
=(8+252)×2-4×23=
=260×2-4×23=
=520-92=
=428
{8+2x[9+9x(7+2x3)]}x2-4x23 = {8+2x[9+9x(7+9)]}x2-92 = [8+2x(9+9x16)]x2-92=[8+2x(9+144)]x2-92=(8+2x153)x2-92=(8+306)x2-92=314x2-92=628-92=536