cazul
I
5m(<A)=5(<B)=2m(<C)=k
m(<A)=m(<B)=k/5;
m(<C)=k/2
m(<A+<B+<C)=180°
k/5+k/5+k/2=180°
9k=1800°
=>k=200°
m(<A)=m(<B)=200/5=40°
m(<C)=200/2=100°
cazul
II
2m(<A)=2(<B)=5m(<C)=k
m(<A)=m(<B)=k/2;
m(<C)=k/5
m(<A+<B+<C)=k/2+k/2+k/5=180°
6k=900
=> k=150
m(<A)=m(<B)=150/2=75°
m(<C)=150/5=30°
R:
40°,40° si 100° sau 75°, 75° si 30°
