a) AB= x = AB = 0.6BC , = 0,6BC = 14.4
BC = 14.4 x6 = 24cm.
BC= diametru , de unde reiese ca raza va fi BC/2 = 24/2 = 12 cm.
b)
Perimetrul figurii = Parc de cerc BC + P ABCD
P arc cerc BC = P cerc/2 = 2pi r = 2xpix12 = 24 pi cm
P ABCD = 2(L+l) = 2(14.4+24) = 2x38.4 = 76,8cm
= Perimetrul figurii = 24pi cm + 76.8 cm factor comun 4.
4(6pi + 19,4)cm
c) aria = aria disc/2 + A ABCD = pi r la a 2-a = 144pi + 14.4x12 =172.8+144pi cm patrati
